Awesome work!! $\frac{-b\pm \sqrt{b^2+4ac}}{2a}$
Thanks!!!

$x^2$

That is great! Let me test:
$\sqrt{3x-1}+(1+x{)}^2$
It would be cool to integrate with Aloha Editor in some way. The problem is how to define the workflow, but looks very cool…

\lim_{n\rightarrow \infty}\sum_{i=0}^n \frac{1}{p_i}

$\underset{n\to \mathrm{\infty }}{lim}\sum _{i=0}^n\frac{1}{p_i}$

Not bad if I can write Einstein’s equation!

$E=m{c}^2$

Hi, great works.
May I have the link to the code where you integrate writemaths with wysiwyg editor? I cannot get it to work. Thanks for your help

Do you mean in WordPress? I haven’t got it to work in WordPress’s wysiwyg editor.

Can you give me a link of demo to use it in Tinymce?

$\sum _{m=1}^{\mathrm{\infty }}\sum _{n=1}^{\mathrm{\infty }}\frac{m^{2}n}{3^m(m{3}^n+n{3}^m)}$

Great work !

Are you able to get it work on any wysiwyg editor?

$iin{t}_2^{4}x{y}^2.dz$

\iint _{ 2 }^{ 4 }{ x{ y }^{ 2 } } .dz

$$e^{\pi i}+1=0$$

This is cool!

x^2

Again with dollar signs

$x^2$

$x^2$

$x^3+x^2+sqrt(4)$

$$1+\frac{q^2}{(1-q)}+\frac{q^6}{(1-q)(1-q^2)}+\cdots =\prod _{j=0}^{\mathrm{\infty }}\frac{1}{(1-q^{5j+2})(1-q^{5j+3})},\text{for }|q|<1.$$

cool man..

$x=\frac{-b\pm \sqrt{b^2–4ac}}{2a}$

$I=\frac{1^3}{2}m{R}^2=\frac{1}{2}.1.(0,2{)}^2=0,02kg.m^2$

$a^2+b^2=c^2$

Let $a=n_1{p}_j$ where $p_j\in \{2,3,5,7,\dots \},$ so $a\in {P_n}_1.$ Let $b=n_2{p}_k$ where $p_k\in \{2,3,5,7,\dots \},$ so $b\in {P_n}_2.$

Now assume that ${P_n}_1\cap {P_n}_2$ is nonempty. Then there exists some $n_1$ and $n_2$ such that for some $p_j$ and $p_k$ such that $a=b$. Thus we have $n_1{p}_j=n_2{p}_k$.

Note that $p_k{p}_j=p_k{p}_j$ is clearly true, and multiplying both sides of the equation by some integer $m$ gives us $m{p}_k{p}_j=m{p}_k{p}_j$.

So let $n_1=m{p}_k$ and $n_2=m{p}_j$, which implies $n_1{p}_j=n_2{p}_k$, and thus $a=b$ as desired. This means that ${P_n}_1\cap {P_n}_2$ is guaranteed to be nonempty if we can divide any common factors from $n_1$ and $n_2$ and be left with only prime numbers.

(A) is out as $1$ is not prime. (B) is is out because if we divide $7$ and $21$ by their common factor $7$, we are left with $1$ and $7$, and $1$ is not prime. (D) is out because $24/4=6$ which is not prime. (E) is out because $5/5=1$ is not prime. (C) is correct as $12/4=3$ and $20/4=5$, which are both prime.

$$sqrt(4)$$

$sqrt(4)$

$J_{\alpha }(x)=\sum _{m=0}^{\mathrm{\infty }}\frac{(-1{)}^m}{m!\mathrm{\Gamma }(m+\alpha +1)}{\left(\frac{x}{2}\right)}^{2m+\alpha }$

Amazing !

$$\frac{\partial f}{\partial t}=\frac{{\partial }^{2}f}{\partial x^2}$$

I will try to install it on my own wordpress. Thanks a lot !

$a^2+b^4

${\log }_2\left(\frac{1}{x+2}\right)$

a $x+1$
$$\begin{array}{rl}x& =1\\ y& =2\\ z& =3\end{array}$$

$[–\frac{{\hslash }^2}{2m}\frac{{\partial }^2}{\partial x^2}+V]\mathrm{\Psi }=i\hslash \frac{\partial }{\partial t}\mathrm{\Psi }$\

test

$$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}.$$

$$x^2$$

גכשדכשד $$5x+3^2=3$$

I wish music was as easy to work with as math… $$E\mathrm{♭}=D\mathrm{♯}$$

$$x=\sqrt{\frac{2x+3y^2+2}{2x+y}}+a^3+b^2+4$$

$\frac{1}{(\sqrt{\varphi \sqrt{5}}-\varphi )e^{\frac{2}{5}\pi }}=1+\frac{e^{-2\pi }}{1+\frac{e^{-4\pi }}{1+\frac{e^{-6\pi }}{1+\frac{e^{-8\pi }}{1+\cdots }}}}$

$$y=acos(\frac{t}{p}qx)$$

\texttt{dst} (I) = \fork{\texttt{src}(I)^power}{if \texttt{power} is integer}{|\texttt{src}(I)|^power}{otherwise}

y = $\sqrt{(}{x}^2+2x^3)$

$$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$